This animation walks through solving the linear inequality 4(x-3)-4x+10 < 3(x-4)+7 by expanding brackets, combining like terms on each side, and isolating the variable through addition and division. Each algebraic move is shown clearly, ending with the solution x > 1. It helps students see how inequality rules mirror equation-solving steps, with the key reminder that the inequality direction stays the same when dividing by a positive number. Useful for middle or early high school algebra practice.
Narrated · 16:9 · Preview before teaching · automatic layout checks do not establish subject accuracy
Langkah 1: Membuka tanda kurung Kalikan setiap bilangan di luar kurung dengan setiap suku di dalam kurung. \[ 4x-12-4x+10<3x-12+7 \] Langkah 2: Menyederhanakan kedua ruas Pada ruas kiri: \[ 4x-4x-12+10=-2 \] Pada ruas kanan: \[ 3x-12+7=3x-5 \] Sehingga diperoleh: \[ -2<3x-5 \] Langkah 3: Memindahkan bilangan ke ruas kiri Tambahkan 5 pada kedua ruas. \[ -2+5<3x-5+5 \] \[ 3<3x \] Langkah 4: Menentukan nilai \(x\) Bagi kedua ruas dengan 3. \[ \frac{3}{3}<\frac{3x}{3} \] \[ 1<x \] Artinya: \[ x>1 \]