This animation solves two equilibrium problems in Arabic narration with English equations. First, a hanging metal block stretches a spring with k = 200 N/m by 0.15 m, showing that spring force equals weight to find W = 30 N. Second, a free-body diagram for a 6.0 kg lamp supported by two cables at 40° demonstrates how vertical force balance gives tension T = 45.7 N per cable. Useful for students practicing Hooke's Law and vector resolution in static equilibrium.
Narrated · 16:9 · Preview before teaching · automatic layout checks do not establish subject accuracy
Scene 7: Spring Extension & Exam Question (Problems 6 & 7)Problem 6 (Try - Part C: Hanging Metal Block on Spring):Visual Prompt: A metal block hanging in equilibrium from a vertical spring with spring constant k = 200 N/m, stretching it by x = 0.15 m. Voiceover & Step-by-Step Breakdown:Given: Spring Constant k = 200 N/m, Stretch distance x = 0.15 m. Concept: In equilibrium, spring force (Fe = k * x) equals the weight of the block (W). Calculation: W = k * x = 200 * 0.15 = 30 N. Problem 7 (Exam Question - 6.0 kg Lamp Free-Body Diagram):Visual Prompt: Drawing a Free-Body Diagram for a 6.0 kg lamp supported symmetrically by two cables at 40° to the horizontal. Voiceover & Step-by-Step Breakdown:Given: m = 6.0 kg, W = 6.0 * 9.8 = 58.8 N, θ = 40°. FBD Setup: Downward vector W = 58.8 N, two upward diagonal vectors T at 40°. Calculation: 2 * T * sin(40°) = 58.8 => T = 58.8 / (2 * 0.643). Result: T = 45.7 N in each cable. IMPORTANT LANGUAGE RULE: All on-screen text must be in Arabic EXCEPT mathematical equations, formulas, laws, symbols, variables, and numerical expressions. Keep every equation, formula, and law exactly as provided, without translating or changing it. Translate only the explanatory text, headings, labels, and descriptions into Arabic. Arabic text must use proper RTL direction and correct Arabic typography. Do not use English text anywhere else on the screen. Audience: student