A worked-solutions animation covering four exam-style projectile motion problems on a blackboard format, showing given values, substitution steps, and boxed final answers. Topics include time of flight, horizontal range, impact speed from velocity components, and working backward from landing points to find initial speed and required height. Useful for students preparing for physics exams and teachers reviewing kinematics problem-solving techniques.
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Scene 5: Comprehensive Exercise Session (Page 6 - Bottom Half) Visual Description: Full-screen animated blackboard showing four multi-part exam-style physics problems. Each problem is presented with given values, step-by-step mathematical substitution, and final boxed answers. PDF + 1 Voiceover / Audio Script: "Let's solve the complete set of exam exercises from page 6 step by step." PDF On-Screen Text Overlay (To be displayed in video / PPT): Exercise (a): Given: v 0 =9.8 m/s , y=14.7 m , g=9.8 m/s 2 . PDF (i) Time ( t ): t= 9.8 2×14.7 = 3 ≈1.73 s PDF (ii) Range ( x ): x=9.8×1.73≈16.95 m PDF (iii) Impact Speed ( v ): v x =9.8 m/s PDF v y =9.8×1.73=16.95 m/s PDF + 1 v= 9.8 2 +16.95 2 ≈19.58 m/s PDF + 1 Exercise (b): Given: v 0 =6.0 m/s , t=2.0 s , g=9.8 m/s 2 . PDF (i) Initial Height ( y ): y= 2 1 ×9.8×2.0 2 =19.6 m PDF + 1 (ii) Range ( x ): x=6.0×2.0=12.0 m PDF + 1 Exercise (c): Given: Initial y 1 =0.40 m , x 1 =0.40 m (Point A). PDF (i) Time to Point A ( t 1 ): t 1 = 9.8 2×0.40 = 0.0816 ≈0.286 s PDF (ii) Initial Speed ( v 0 ): v 0 = t 1 x 1 = 0.286 0.40 ≈1.40 m/s PDF (iii) Height for Point B ( x 2 =0.80 m ): Time needed: t 2 = v 0 x 2 = 1.40 0.80 =0.571 s PDF Height required: y 2 = 2 1 ×9.8×(0.571) 2 ≈1.60 m PDF + 1 Exam Style Question (Rolling Ball): Given: y=1.25 m , v 0 =2.0 m/s , g=9.8 m/s 2 . PDF (a) Time to reach ground ( t ): t= 9.8 2×1.25 = 0.255 ≈0.505 s PDF (b) Horizontal Distance ( x ): x=2.0×0.505≈1.01 m PDF write only equationa and laws in english and every thing els in arabic Audience: student