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Solving Horizontal Projectile Motion Problems

A split-screen animation walks through three worked examples of horizontal projectile motion, starting with a phone sliding off a ledge. Step-by-step equations reveal how falling height sets the time of flight while horizontal velocity sets the range, then combine to find impact speed. Useful for physics students practicing kinematics equations and for teachers demonstrating how to structure multi-part projectile motion solutions.

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The prompt that made it

Scene 3: Quick Applications & Practice Problems (Page 5 - Top Half)Visual Description: A dynamic split-screen showing a falling smartphone slipping off a window ledge, followed by two diagrammatic trajectory setups for horizontal projectile calculations. Animated equations pop up step-by-step as each problem is solved. Voiceover / Audio Script: "Let's solve three core problems on horizontal projectiles. Remember: height determines the time of flight, while horizontal velocity determines the range." On-Screen Text Overlay (To be displayed in video / PPT):Key Concept: Height determines flight time ($t$). Horizontal velocity determines range ($x$). Problem 1 (Phone Drop):Question: A phone slides off a ledge $y = 4.9\text{ m}$ high. Find time of fall. Solution:$t = \sqrt{\frac{2y}{g}} = \sqrt{\frac{2 \times 4.9}{9.8}} = \sqrt{1} = 1.0\text{ s}$ Problem 2 (Try Yourself - Part A):Given: $v_0 = 19.6\text{ m/s}$, $y = 58.8\text{ m}$, $g = 9.8\text{ m/s}^2$. (i) Time of flight ($t$):$t = \sqrt{\frac{2 \times 58.8}{9.8}} = \sqrt{12} \approx 3.46\text{ s}$ (ii) Horizontal Range ($x$):$x = v_0 \cdot t = 19.6 \times 3.46 = 67.8\text{ m}$ (iii) Impact Speed ($v$):$v_x = 19.6\text{ m/s}$ $v_y = g \cdot t = 9.8 \times 3.46 = 33.9\text{ m/s}$ $v = \sqrt{19.6^2 + 33.9^2} = \sqrt{384.16 + 1149.21} \approx 39.16\text{ m/s}$ Problem 3 (Try Yourself - Part B):Given: $v_0 = 3.0\text{ m/s}$, $t = 3.0\text{ s}$, $g = 9.8\text{ m/s}^2$. (i) Initial Height ($y$):$y = \frac{1}{2} g \cdot t^2 = 0.5 \times 9.8 \times 3.0^2 = 44.1\text{ m}$ (ii) Horizontal Range ($x$):$x = v_0 \cdot t = 3.0 \times 3.0 = 9.0\text{ m}$ write only equationa and laws in english and every thing els in arabic Audience: student

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